Questions tagged [frequency-severity]
7 questions
9
votes
1 answer
Tweedie p parameter Interpretation
From Wikipedia (http://en.wikipedia.org/wiki/Tweedie_distribution) we know that
The Tweedie distributions include a number of familiar distributions as well as some unusual ones, each being specified by the domain of the index parameter. We have…
Eric
- 820
- 1
- 7
- 18
3
votes
0 answers
Changepoint Analysis in R for Time Series Data
I'm new to R and statistics in general. My background is in Software Development, and I've tasked myself to solve a problem in a 3rd party application. This application is a Game, and I'd like to measure the existence of a performance problem.
I…
Israel Lopez
- 131
- 1
2
votes
0 answers
Ordinal logistic model in R
I have the neuropsychiatric questionnaire scores of 300 individuals, of which 200 are normal, and 100 have the disease. The questionnaire is divided into 12 categories (delusion, agitation, ... etc). And each category begins with a question along…
Adrian
- 1,665
- 3
- 22
- 42
1
vote
0 answers
Determining rating function for severity measure
I have data of a medical experiment and want to run a linear regression. More precisely, I have severity degrees of a disease of two independent groups (treatment and control group). The severity degrees are categorical with values {0,1,2,3} (0…
Paul85
- 111
- 1
0
votes
0 answers
Simplifying severity score
I'm hoping for general advice on how to tackle a problem. There is an existing 10-item severity score.
I have data on 1000 patients; specifically, I have the score for each item, the overall score (calculated by summing the score for each item) &…
NotLost
- 11
- 1
0
votes
1 answer
Find $E[N^2 | N > 2]$ for a frequency distribution
N has probability mass function: $p_o = p_1 =0$ and $p_k = \frac{1}{(e^1-2)k!}$ for $k=2,3,4,...$ I Solved for the pgf of N and got $G(t) = \frac{e^t}{e^1-2}$
How do I calculate $E[N^2 | N>2]$?
-1
votes
1 answer
Finding C for a PMF of a frequency distribution
N has probability mass function: $p_o = p_1 =0$ and $p_k = c/k!$ for $k=2,3,4,...$ I used exp series $\sum_{n=1}^{\infty} \frac{x^k}{k!} = e^x$ to get $ c\sum_{n=1}^{\infty} \frac{1}{k!}$ then $ce=1$ to get $c = 1/e$ Did I do something wrong?