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I've been reading the post about removing intercept that boosts $R^2$ (HERE). An answer to that post said that:

In essence, that means our predictor had better have a strong mean offset itself and that this mean offset should dominate the variation of the predictor.

My question is: what is "a predictor mean offset"? I've searched the Internet and found nothing :(

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Lil'Lobster
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    The quotation is a summary of the detailed explanation that precedes it. You could take the preceding paragraph as @Cardinal's *definition* of "strong mean offset." – whuber Aug 13 '14 at 18:28
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    I like definitions by "X is sth, that...". Taking the paragraph does not change anything - I still don't understand, that's why I decided to ask a direct question. – Lil'Lobster Aug 13 '14 at 18:34

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