The question and related table is given in the picture. I applied bayes rule as:
$\cfrac{P(X_1=-1,X_2=1|C_1)}{P(X_1=-1,X_2=1)} = \cfrac{P(X_1=-1|C_1)P(X_2=1|C1)P(C_1)}{P(X_1=-1|C_1)P(X_2=1|C1)P(C_1) + P(X_1=-1|C2)P(X_2=1|C2)P(C_2)}$
From the table, I think:
$P(X_1=-1|C_1)=0.2$
$P(X_2=1|C1)=0.1$
$P(X_1=-1|C2)=0.3$
$P(X_2=1|C2)=0.6$
I couldn't make anything about $P(C_1)$ and $P(C_2)$. May you please help me? Thanks in advance for your replies.
Edit:Picture is added!