If $X\sim U , Y\sim U$ , and $X,Y$ may be non-independent. Can we say the joint distribution of $X,Y$ is uniform?
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kjetil b halvorsen
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aditer
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4A term that might interest you is *copula*. – Dave Aug 09 '21 at 18:05
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2Consider the case $X=Y.$ – whuber Aug 09 '21 at 21:32
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See [Is there a bivariate β distribution I can fit to my data?](https://stats.stackexchange.com/questions/315865/is-there-a-bivariate-beta-distribution-i-can-fit-to-my-data/535945#535945) for examples! (choose the parameters so that the marginals are uniform). – kjetil b halvorsen Aug 10 '21 at 00:43
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3Consider a chessboard, and imagine the probability is uniform on the white squares – Thomas Lumley Aug 10 '21 at 01:29
2 Answers
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No, the joint distribution is not necessarily uniform.
Consider $X$ and $Y$ with a joint pdf
$$ f(x,y) = \begin{cases} 2, \text{if } x \in (0,0.5), y \in (0,0.5)\\ 2, \text{if }x \in (0.5,1), y \in (0.5,1) \\ 0, \text{otherwise} \end{cases} $$
Then both $X$ and $Y$ have marginal $U(0,1)$ distributions, but the joint distribution is not uniform.

David Luke Thiessen
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1+1 [I put together a visualization of your density.](https://i.stack.imgur.com/lE8kZ.png) `set.seed(2021); N – Dave Aug 09 '21 at 18:25
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Suppose that $X\sim Unif(0,1)$ and $Y\sim Unif(0,X)$, then the joint distribution will be
$$f(X,Y)=f(Y|X)f(X)=\frac{1}{x}, \ \ \ 0\leq y \leq x\leq 1$$
If I'm not mistaken a uniform distribution gives the same importance to the whole domain of $(X,Y)$, whereas in the case displayed the importance given depends on the sampled $X$.

Fiodor1234
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I think it's worth noting that although $Y|X \sim Unif(0,X)$, the marginal distribution of $Y$ is not uniform. – David Luke Thiessen Aug 10 '21 at 15:02
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If the parameter of interval is a random variable, it is a uniform disturbution? In fact, many definitions do not clearly indicate this problem. Anyway, copula is a better interpretation to solve this question for me. – aditer Oct 08 '21 at 16:16