In Epidemiology An Introduction Chapter 9,p165:CI for Risk data and Prevalence data:
95% CI= R±1.96×SE(R)SE(R)=[a(N-a)/N³]½
In Epuation,R=a/N,a to represent cases and N to represent people at risk. But how do I get an asymmetrical confidence interval for population rate like this?
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See https://stats.stackexchange.com/search?q=logistic+regression+confidence+interval. The following refinement of that search produces many applicable posts: https://stats.stackexchange.com/search?q=logistic+regression+confidence+interval+answers%3A1+score%3A2. – whuber Apr 28 '21 at 14:31