There is a committee of 18 people, and a board of 5 people will be randomly chosen. What is the probability John, Jane, and Randy will all 3 be on the board of 5?
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There are 18C5 = 8568 boards. If 3 particular people are on a board, this leaves 15 people from which to choose the remaining two. 15C2 = 105. Probability = 105/8568 = .012 rounded.
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