Does quadratic loss find the median of the prior distribution? Someone told me linear loss finds the mean, all-nothing loss function finds the mode of the prior.
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Minimizing the absolute error will lead to the median of the distribution. I assume "linear loss" is the same as "absolute error".
Minimizing the squared error will lead to the mean of the distribution. This is a standard result in introductory probability theory or statistics.
Minimizing the all-or-nothing loss will lead to the mode of the distribution (assuming it can take only a finite or countable number of values - if it is continuous, all-or-nothing loss has an expected value of zero for all single values).

Stephan Kolassa
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