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I am interested in a nice function to find the area of a section of a normalized Gaussian distribution. Let's say I have a normalized Gaussian distribution of standard deviation $\sigma$, mean $\mu$, and I am interested in the area centered at $\mu$ between +/- $t$ ( see below) enter image description here

Is there a simple way to express this for any given $t$ using the erf? The ref from which I found the above figure uses

$$a_1 = 2 \mathrm{erf}\left(\frac{t}{\sigma} \right) $$

But I don't think this expression is true for a normalized guassian. Moreover, can the $\textit{total}$ area be expressed by an error function?

Thanks, very new to statistics.

Jimbo
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1 Answers1

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This question has already been answered here. Note that you can compute the integral over a finite interval by means of the CDF $\Phi$: $$\int_a^b \varphi(x)\,dx = \Phi(b) - \Phi(a)$$

cdalitz
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