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The question asks to find $ \chi^{2*} $ that cuts off 5% of the tail with df=52. the chart given lists df=50 then jumps to 60

Mitch Hughes
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  • You may want to remove the `*` from your body text as well. Your question is covered in the answer here: [How do I find values not given in (interpolate in) statistical tables?](http://stats.stackexchange.com/questions/64538/how-do-i-find-values-not-given-in-interpolate-in-statistical-tables/64539#64539) – Glen_b Nov 25 '15 at 21:53
  • in the title it was an error, in the question it just means a specific value of $\chi^2$ opposed to the whole range – Mitch Hughes Nov 25 '15 at 21:56
  • It's probably more confusing than enlightening. I'd suggest "find the $\chi^2$ value that..." – Glen_b Nov 25 '15 at 21:58
  • When you say "the question asks" .... is this for a class? – Glen_b Nov 25 '15 at 21:59
  • Specifically, note that for degrees of freedom for $t$, $\chi^2$ and $F$ the linked answer recommends linear interpolation in $1/\text{df}$ rather than in $\text{df}$. However in this particular case, linear interpolation in $\text{df}$ is actually very good, slightly better than inverse interpolation in df; I'd stick with that for this case (which is what the first half of the linked post is about). – Glen_b Nov 25 '15 at 22:09

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I would take the data from df=50 in this case. If it was 55--> average

Espe FG
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  • (-1) This is not interpolation at all. If you're going to average for $df=55$, which *is* (linear) interpolation, then why not linearly interpolate for $df=52$? Why introduce such an inconsistency, especially when the error made when replacing $52$ by $50$ is substantial? – whuber Nov 25 '15 at 22:03