The following table is of UK domiciled university applicants to UK universities in $2013$ and of acceptances, grouped by self-declared disability.
A $\chi^2$ test on the numbers shows an extremely statistically significant difference between the groups (perhaps suggesting that acceptances are not completely random) even though the quoted two columns of percentages are the same when rounded to one decimal place. This curiosity is related to the large numbers involved, discussed in another question.
The differences in success rates between groups is not large: they in fact range from $72.7\%$ for those declaring a mental health condition to $80.8\%$ for those declaring an autistic spectrum disorder or Asperger's Syndrome, with a figure of $77.2\%$ both overall and for the large majority with no disability declared.
What is a good measure of how close the distributions of applications and acceptances are?
How should the fact that most individuals are in a single subgroup be taken into account? If the total number of acceptances is fixed then the success rate for those with no disability declared must be within the range $75.2\%$ to $83.9\%$ even if everybody else was accepted or everybody else was rejected.
Disability Applicants Acceptances
No. % No. %
Autistic spectrum disorder or
Asperger's Syndrome 2,635 0.5 2,130 0.5
Blind or partially sighted 565 0.1 440 0.1
Deaf or serious hearing impairment 1,035 0.2 805 0.2
Long standing illness (e.g. diabetes,
epilepsy, heart condition) 4,515 0.8 3,355 0.8
Mental health condition 5,170 0.9 3,760 0.9
Specific learning difficulty (e.g.
dyslexia, dyspraxia) 23,480 4.2 18,085 4.2
Physical impairment or
mobility difficulties 1,325 0.2 1,020 0.2
Other disability or medical condition 4,795 0.9 3,755 0.9
Two or more of the above 1,695 0.3 1,275 0.3
No disability declared 518,105 92.0 400,065 92.0
Totals* 563,319 100 434,688 100
Using R:
applic <- c(2635, 565, 1035, 4515, 5170, 23480, 1325, 4795, 1695, 518105)
accept <- c(2130, 440, 805, 3355, 3760, 18085, 1020, 3755, 1275, 400065)
chisq.test(cbind(accept, applic - accept))
gives
Pearson's Chi-squared test
data: cbind(accept, applic - accept)
X-squared = 107.5192, df = 9, p-value < 2.2e-16