According to the info in the following locations:
- http://en.wikipedia.org/wiki/Truncated_normal_distribution
- http://en.wikipedia.org/wiki/Truncated_distribution
- http://lagrange.math.siu.edu/Olive/ch4.pdf
- http://people.sc.fsu.edu/~jburkardt/presentations/truncated_normal.pdf
- http://web.tecnico.ulisboa.pt/~mcasquilho/compute/qc/,truncG/lecture4k.pdf
The probability density function for a left-truncated normal distribution should be:
$f(x) = {{1 \over \sigma}\phi({{x-\mu} \over \sigma})\over{1-\Phi({{a-\mu} \over \sigma})}}$
for all x >= a
However, I'm getting some weird results when I do that.
if I take $\sigma$ = 1.0 and $\mu$=0.0 and $a$=1.0, that gives:
$f(x) = {\phi(x) \over {1-\Phi(1)}}$
If I then plugin a number near the truncation point (say 1.1), I get:
$f(x) \approx {0.212 \over {0.159}} \approx 1.3$
Clearly that's wrong (the PDF should be in the range (0.0, 1.0) for all X).
Except, everywhere I look leads me to the definition of f above, so I can't figure out what I'm doing wrong.
Clearly though, I've gotten something wrong.
I know this is an embarrassingly simple question, but I'd appreciate any help you might be able to give. Do you know what I'm doing wrong?