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How to prove that if $x$ satisfies

$x^n+a_{n-1}x^{n-1}+\dots+a_0 = 0$

for some integers $a_{n-1}$, ..., $a_0$, then $x$ is irrational unless x is an integer.

Thanks for your help in advance.

user26857
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Henry Choi
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1 Answers1

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Suppose $x=\frac p q$ is a root where $p$ and $q$ are integers, $q >0$ and $(p,q)=1$. Then $p^{n}+a_{n-1} p^{n-1}q+\cdots+a_oq^{n}=0$. This implies that $q$ divides $p^{n}$. But $(p,q)=1$ so $q$ must be $1$. So $x$ is an integer.

Kavi Rama Murthy
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