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Can you check please my proof of this inequality? It's all right?

enter image description here

Zain Patel
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PersonaNonGrata
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  • See an easier proof of (a) at this question [here](http://math.stackexchange.com/questions/127372/reverse-triangle-inequality-proof) – JMoravitz Jul 01 '15 at 15:16

2 Answers2

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It's all right, but in point b) you have mistake: need $\ge$, not $\le$.

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Most of your proof is right, while some errors occur in part b).
First, you need to prove that $|x+x_1+\cdots+x_n|\color{red}\ge|x|-(|x_1|+\cdots+|x_n|)$.
Also, it should be $|x|\le|\color{red}x+x_1+\cdots+x_n|+|-x_1|+\cdots+|-x_n|$.

Eclipse Sun
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